What is the domain of f(x)=sqrt(2x+x-x^2) ?

The domain of f(x)=sqrt(2x+x-x^2) is 0<= x<= 3

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domain of f(x)=sqrt(2x+x-x^2)

domain

f (x) = 2 x + x - x^{2}

0 \leq x \leq 3

Interval Notation

[0, 3]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 3

The function domain

0 \leq x \leq 3

f (x) = \frac{- 3}{x - 2} - 1

f (x) = \frac{3 x}{( x - 1 ) ( x - 3 )} - \frac{2}{x - 3}

8 x^{2} - 48 x

\frac{- 1 - 1 - 20 x}{10}

f (x) = ln (8 x - 8)

What is the domain of f(x)=sqrt(2x+x-x^2) ?
The domain of f(x)=sqrt(2x+x-x^2) is 0<= x<= 3