What is the critical f(x)=(x^2)/(x-2) ?

The critical f(x)=(x^2)/(x-2) is x=0,x=4

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critical f(x)=(x^2)/(x-2)

critical points

f (x) = \frac{x ^{2}}{x - 2}

x = 0, x = 4

Solution steps

\frac{x ^{2}}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x - 2} : x < 2 or x > 2

\frac{x ^{2}}{x - 2}

is not defined at

x = 2

, therefore:

x = 0, x = 4

\frac{1}{x ^{2} - 2}

3 x + 4 y = 5, at (\frac{- 2 , 4}{7})

f (x) = x^{2} + 11

lo g_{4} (x^{3} + 2)

6 - \frac{1}{2} x

What is the critical f(x)=(x^2)/(x-2) ?
The critical f(x)=(x^2)/(x-2) is x=0,x=4