What is the domain of f(x)=1-ln(5x-1) ?

The domain of f(x)=1-ln(5x-1) is x> 1/5

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domain of f(x)=1-ln(5x-1)

domain

f (x) = 1 - ln (5 x - 1)

x > \frac{1}{5}

Interval Notation

(\frac{1}{5}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{5}

The function domain

x > \frac{1}{5}

f (x) = \frac{( 2 x )}{( x ^{2} - 3 x + 2 )}

- \frac{1}{4} - 5

f (x) = 9 - 7 \cdot 10 - 2 x

\frac{arcsin ( \frac{x}{2} )}{6}

\frac{1}{3 - ( \frac{x}{x - 1} )}