What is the domain of y=sqrt(2x^2-3x-2) ?

The domain of y=sqrt(2x^2-3x-2) is x = 2

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domain of y=sqrt(2x^2-3x-2)

domain

y = 2 x^{2} - 3 x - 2

x \leq - \frac{1}{2} or x \geq 2

Interval Notation

(- \infty, - \frac{1}{2}] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{1}{2} or x \geq 2

The function domain

x \leq - \frac{1}{2} or x \geq 2

f (x) = (x + 1)^{3} (x - 2)^{2}

\frac{x - 6}{x - 4}

f (x) = \frac{x ^{3} + 4 x ^{2} + x - 6}{x ^{2} + 2 x - 3}

14 - (x + 6)

lo g_{10} (2) (x + 2)

What is the domain of y=sqrt(2x^2-3x-2) ?
The domain of y=sqrt(2x^2-3x-2) is x<=-1/2 \lor x>= 2