What is the domain of f(x)=(x^3+4x^2+x-6)/(x^2+2x-3) ?

The domain of f(x)=(x^3+4x^2+x-6)/(x^2+2x-3) is x 1

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domain of f(x)=(x^3+4x^2+x-6)/(x^2+2x-3)

domain

f (x) = \frac{x ^{3} + 4 x ^{2} + x - 6}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

14 - (x + 6)

lo g_{10} (2) (x + 2)

y = 4 x^{3} + x

g (x) = 3^{x} + 1

f (x) = x^{2} + x - 2

What is the domain of f(x)=(x^3+4x^2+x-6)/(x^2+2x-3) ?
The domain of f(x)=(x^3+4x^2+x-6)/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1