What is the domain of f(x)=x^2+sqrt(x-2) ?

The domain of f(x)=x^2+sqrt(x-2) is x>= 2

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domain of f(x)=x^2+sqrt(x-2)

domain

f (x) = x^{2} + x - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{x ^{3} + 3 x ^{2}}{5 x ^{2} - 1}

f (x) = \frac{7 x + ∣ x ∣}{x}

f (x) = \frac{1}{2} sin (2 x) - cos (x)

\frac{1}{\frac{5}{- 8 x - 10} + 2}

f (x) = \frac{x - 3}{x ^{2} - 2 x - 15}

What is the domain of f(x)=x^2+sqrt(x-2) ?
The domain of f(x)=x^2+sqrt(x-2) is x>= 2