What is the domain of sqrt(x^2+6x+8) ?

The domain of sqrt(x^2+6x+8) is x =-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(x^2+6x+8)

domain

x^{2} + 6 x + 8

x \leq - 4 or x \geq - 2

Interval Notation

(- \infty, - 4] \cup [- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq - 2

The function domain

x \leq - 4 or x \geq - 2

f (x) = \frac{5 x}{x + 5}

f (x) = (2 + x^{2}) e^{2 x}

\frac{3 x + 54}{3 ^{x} - 81} + 19 - x^{4}

y = \frac{x ^{2}}{4 - x}

f (t) = t + 3

What is the domain of sqrt(x^2+6x+8) ?
The domain of sqrt(x^2+6x+8) is x<=-4\lor x>=-2