What is the domain of f(x)=(x^2-10x-56)/(2x^2+8x) ?

The domain of f(x)=(x^2-10x-56)/(2x^2+8x) is x 0

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domain of f(x)=(x^2-10x-56)/(2x^2+8x)

domain

f (x) = \frac{x ^{2} - 10 x - 56}{2 x ^{2} + 8 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

f (t) = t + 2

f (x) = \frac{6 x}{5 x - 2}

f (x) = \frac{( 12 - x - x ^{2} )}{x + 2}

f (x) = - 3 x^{2} + 6 x + 1

f (x) = 2 x y - 3 y = 2 - 3 x

What is the domain of f(x)=(x^2-10x-56)/(2x^2+8x) ?
The domain of f(x)=(x^2-10x-56)/(2x^2+8x) is x<-4\lor-4<x<0\lor x>0