What is the domain of f(x)=(3x^2+6x+9)/(x^2+4x+3) ?

The domain of f(x)=(3x^2+6x+9)/(x^2+4x+3) is x -1

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domain of f(x)=(3x^2+6x+9)/(x^2+4x+3)

domain

f (x) = \frac{3 x ^{2} + 6 x + 9}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

f (x) = \frac{( 11 )}{x - 4}

y = \frac{4}{x ^{2} + 4} + \frac{7}{x ^{2} - 9}

f (x) = ln (x^{2} - 4) + π

3 + x - 6

f (x) = 12 x^{2} - 5 x - 150

What is the domain of f(x)=(3x^2+6x+9)/(x^2+4x+3) ?
The domain of f(x)=(3x^2+6x+9)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1