What is the domain of y= 4/(x^2+4)+7/(x^2-9) ?

The domain of y= 4/(x^2+4)+7/(x^2-9) is x 3

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domain of y= 4/(x^2+4)+7/(x^2-9)

domain

y = \frac{4}{x ^{2} + 4} + \frac{7}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = ln (x^{2} - 4) + π

3 + x - 6

f (x) = 12 x^{2} - 5 x - 150

f (x) = ln (0.5) - 0.5

f (x) = 3 + tan (x + \frac{π}{2})

What is the domain of y= 4/(x^2+4)+7/(x^2-9) ?
The domain of y= 4/(x^2+4)+7/(x^2-9) is x<-3\lor-3<x<3\lor x>3