What is the domain of f(x)=3+tan(x+pi/2) ?

The domain of f(x)=3+tan(x+pi/2) is pin<x<pi+pin

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domain of f(x)=3+tan(x+pi/2)

domain

f (x) = 3 + tan (x + \frac{π}{2})

πn < x < π + πn

Interval Notation

(πn, π + πn)

Solution steps

Take the denominator(s) of

3 + tan (x + \frac{π}{2})

and compare to zero:

x = πn

Periodicity of

3 + tan (x + \frac{π}{2}) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn < x < π + πn

h (x) = 289 - x^{2}

\frac{x}{7} + \frac{5}{7} + \frac{3 x + 15}{7 ( 7 x ^{2} - 3 )}

3 + x - 4

\frac{n}{x}

8 x^{4} - 40 x^{2}

What is the domain of f(x)=3+tan(x+pi/2) ?
The domain of f(x)=3+tan(x+pi/2) is pin<x<pi+pin