What is the domain of f(x)=(x-1)^2-1 ?

The domain of f(x)=(x-1)^2-1 is -infinity <x<infinity

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domain of f(x)=(x-1)^2-1

domain

f (x) = (x - 1)^{2} - 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{3 x + 5}{x - 2}

f (x) = cos (x) = sin (y)

lo g_{2} (4 x - 3)

f (x) = \frac{4 x ( x - 6 )}{2 x ^{2} - 5 x - 3}

f (x) = \frac{x - 6}{x ^{2} - 1}

What is the domain of f(x)=(x-1)^2-1 ?
The domain of f(x)=(x-1)^2-1 is -infinity <x<infinity