What is the domain of ((x-1)(x+9))/(x^2-9) ?

The domain of ((x-1)(x+9))/(x^2-9) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of ((x-1)(x+9))/(x^2-9)

domain

\frac{( x - 1 ) ( x + 9 )}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = ln ∣ x - 6 ∣

f (x) = ln (1 + 2 x^{2})

\frac{7 x}{3 x - 1}

f (x) = \frac{2 x - 4}{3 x - 5}

f (x) = cos (z)

What is the domain of ((x-1)(x+9))/(x^2-9) ?
The domain of ((x-1)(x+9))/(x^2-9) is x<-3\lor-3<x<3\lor x>3