What is the domain of f(x)=ln(1+2x^2) ?

The domain of f(x)=ln(1+2x^2) is -infinity <x<infinity

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domain of f(x)=ln(1+2x^2)

domain

f (x) = ln (1 + 2 x^{2})

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{7 x}{3 x - 1}

f (x) = \frac{2 x - 4}{3 x - 5}

f (x) = cos (z)

f (x) = 4 - (x^{2})

\frac{- x ^{2} + 6}{x ^{2} + 4 x - 32}

What is the domain of f(x)=ln(1+2x^2) ?
The domain of f(x)=ln(1+2x^2) is -infinity <x<infinity