What is the domain of f(x)=sqrt(x)-sqrt(4-x^2) ?

The domain of f(x)=sqrt(x)-sqrt(4-x^2) is 0<= x<= 2

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domain of f(x)=sqrt(x)-sqrt(4-x^2)

domain

f (x) = x - 4 - x^{2}

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

The function domain

0 \leq x \leq 2

f (x) = x + x - 18

\frac{x - 1}{25 - x ^{2}}

f (x) = \frac{x ^{2} - 3 x - 28}{x + 4}

f (x) = \frac{3}{x - 2} + 2

f (x) = \frac{3}{x - 2} + 4

What is the domain of f(x)=sqrt(x)-sqrt(4-x^2) ?
The domain of f(x)=sqrt(x)-sqrt(4-x^2) is 0<= x<= 2