What is the domain of (sqrt(x^2-4))/(x^2-2x) ?

The domain of (sqrt(x^2-4))/(x^2-2x) is x 2

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domain of (sqrt(x^2-4))/(x^2-2x)

domain

\frac{x ^{2} - 4}{x ^{2} - 2 x}

x \leq - 2 or x > 2

Interval Notation

(- \infty, - 2] \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 0

Combine real regions and undefined points for final function domain

x \leq - 2 or x > 2

- \frac{14}{5} + 26

g (x) = \frac{7 x}{x ^{2} - 16}

f (x) = 3 x^{2} + 5 x + 7

f (x) = (x - 1) + 2

\frac{6 - x}{4 x + 20}

What is the domain of (sqrt(x^2-4))/(x^2-2x) ?
The domain of (sqrt(x^2-4))/(x^2-2x) is x<=-2\lor x>2