What is the domain of f(x)=sqrt((x-1))+2 ?

The domain of f(x)=sqrt((x-1))+2 is x>= 1

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domain of f(x)=sqrt((x-1))+2

domain

f (x) = (x - 1) + 2

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

\frac{6 - x}{4 x + 20}

y = \frac{x + 3}{2 x - 5}

\frac{x ^{3} + 2}{x ^{3} + 1}

f (x) = 4 x - 2 + 1

f (x) = \frac{- 8 x ^{2}}{( x - 7 ) ( x + 3 )}

What is the domain of f(x)=sqrt((x-1))+2 ?
The domain of f(x)=sqrt((x-1))+2 is x>= 1