What is the domain of f(x)=(-8x^2)/((x-7)(x+3)) ?

The domain of f(x)=(-8x^2)/((x-7)(x+3)) is x 7

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domain of f(x)=(-8x^2)/((x-7)(x+3))

domain

f (x) = \frac{- 8 x ^{2}}{( x - 7 ) ( x + 3 )}

x < - 3 or - 3 < x < 7 or x > 7

Interval Notation

(- \infty, - 3) \cup (- 3, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 3

The function domain

x < - 3 or - 3 < x < 7 or x > 7

y = 2 sec (3 x - π) + 1

y = (x + 2)^{2}

f (x) = 22 x - 1694 = 0

f (x) = arctan (\frac{1}{x + 1})

p (x) = 25 - 3 x

What is the domain of f(x)=(-8x^2)/((x-7)(x+3)) ?
The domain of f(x)=(-8x^2)/((x-7)(x+3)) is x<-3\lor-3<x<7\lor x>7