What is the domain of f(x)=arctan(1/(x+1)) ?

The domain of f(x)=arctan(1/(x+1)) is x -1

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domain of f(x)=arctan(1/(x+1))

domain

f (x) = arctan (\frac{1}{x + 1})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

p (x) = 25 - 3 x

(x - 6) - (x + 2)

- x + 4 - x + 4

x^{2} - x + 6

\frac{3 x ^{2} + 1}{4}

What is the domain of f(x)=arctan(1/(x+1)) ?
The domain of f(x)=arctan(1/(x+1)) is x<-1\lor x>-1