What is the domain of f(x)=(sqrt(x-3))/(x^2-9) ?

The domain of f(x)=(sqrt(x-3))/(x^2-9) is x>3

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domain of f(x)=(sqrt(x-3))/(x^2-9)

domain

f (x) = \frac{x - 3}{x ^{2} - 9}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x > 3

4 3 x + 8 + 4

ln (- x^{2} + 5 x + 3)

∣ 2 x + 5 ∣

f (x) = 4 x - 6, x \geq 2

f (x) = \frac{1}{3 x - 1}

What is the domain of f(x)=(sqrt(x-3))/(x^2-9) ?
The domain of f(x)=(sqrt(x-3))/(x^2-9) is x>3