What is the domain of 4sqrt(3x+8)+4 ?

The domain of 4sqrt(3x+8)+4 is x>=-8/3

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domain of 4sqrt(3x+8)+4

domain

4 3 x + 8 + 4

x \geq - \frac{8}{3}

Interval Notation

[- \frac{8}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{8}{3}

The function domain

x \geq - \frac{8}{3}

ln (- x^{2} + 5 x + 3)

∣ 2 x + 5 ∣

f (x) = 4 x - 6, x \geq 2

f (x) = \frac{1}{3 x - 1}

f (x) = \frac{x - 3}{x ^{2} - 4}