What is the domain of y=\sqrt[6]{3-ln(x/4)} ?

The domain of y=\sqrt[6]{3-ln(x/4)} is 0<x<= 4e^3

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domain of y=\sqrt[6]{3-ln(x/4)}

domain

0 < x \leq 4 e^{3}

Interval Notation

(0, 4 e^{3}]

Solution steps

Find non-negative values for radicals:

0 < x \leq 4 e^{3}

The function domain

0 < x \leq 4 e^{3}

f (x) = - x^{3} + 69 x^{2}

\frac{33}{11} \frac{5.5}{11} \frac{16.5}{11}

f (x) = \frac{( - 8 ^{2} )}{( x - 7 ) ( x + 6 )}

f (x) = 2 y - 4 x^{(2)} = 3

x^{2} + 2 x

What is the domain of y=\sqrt[6]{3-ln(x/4)} ?
The domain of y=\sqrt[6]{3-ln(x/4)} is 0<x<= 4e^3