What is the domain of sqrt(x^2+2x) ?

The domain of sqrt(x^2+2x) is x = 0

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domain of sqrt(x^2+2x)

domain

x^{2} + 2 x

x \leq - 2 or x \geq 0

Interval Notation

(- \infty, - 2] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 0

The function domain

x \leq - 2 or x \geq 0

- 5 e^{3 x - 4} + 8

f (x) = \frac{7 ( x ^{2} - 5 x - 6 )}{8 ( x ^{2} - 36 )}

- \frac{x - 2}{2 x - 6}

3.90753 x

What is the domain of sqrt(x^2+2x) ?
The domain of sqrt(x^2+2x) is x<=-2\lor x>= 0