What is the domain of (2x)/(sqrt(x)-1) ?

The domain of (2x)/(sqrt(x)-1) is 0 1

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domain of (2x)/(sqrt(x)-1)

domain

\frac{2 x}{x - 1}

0 \leq x < 1 or x > 1

Interval Notation

[0, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x > 1

f (x) = \frac{x + 3}{2 x ^{2} + 5 x + 2}

\frac{( x + 1 )}{( x ^{2} - 13 x + 42 ) ^{\frac{1}{2}}}

f (θ) = 1 - cos (θ)

f (x) = (x - 2) + - 2 x + 5

\frac{10 x + 7}{3 - 8 x}

What is the domain of (2x)/(sqrt(x)-1) ?
The domain of (2x)/(sqrt(x)-1) is 0<= x<1\lor x>1