What is the domain of ((x+1))/((x^2-13x+42)^{1/2)} ?

The domain of ((x+1))/((x^2-13x+42)^{1/2)} is x 7

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domain of ((x+1))/((x^2-13x+42)^{1/2)}

domain

\frac{( x + 1 )}{( x ^{2} - 13 x + 42 ) ^{\frac{1}{2}}}

x < 6 or x > 7

Interval Notation

(- \infty, 6) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 6 or x \geq 7

Find undefined (singularity) points:

x = 7, x = 6

Combine real regions and undefined points for final function domain

x < 6 or x > 7

f (θ) = 1 - cos (θ)

f (x) = (x - 2) + - 2 x + 5

\frac{10 x + 7}{3 - 8 x}

\frac{( x + 4 )}{( 3 x - 4 )}

f (x) = \frac{x - 2}{x ^{2} - 2 x - 8}

What is the domain of ((x+1))/((x^2-13x+42)^{1/2)} ?
The domain of ((x+1))/((x^2-13x+42)^{1/2)} is x<6\lor x>7