What is the domain of ((sqrt(x+4)))/((sqrt(3x-4))) ?

The domain of ((sqrt(x+4)))/((sqrt(3x-4))) is x> 4/3

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domain of ((sqrt(x+4)))/((sqrt(3x-4)))

domain

\frac{( x + 4 )}{( 3 x - 4 )}

x > \frac{4}{3}

Interval Notation

(\frac{4}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{4}{3}

Find undefined (singularity) points:

x = \frac{4}{3}

Combine real regions and undefined points for final function domain

x > \frac{4}{3}

f (x) = \frac{x - 2}{x ^{2} - 2 x - 8}

f (x) = \frac{x ^{2} - 7}{x ^{2} + 3 x - 4}

f (x) = \frac{x - 8}{x ^{2} - 49}

f (x) = \frac{3 x + 9}{x ^{2} + x - 12}

f (x) = 5 \cdot 1 - x - 3

What is the domain of ((sqrt(x+4)))/((sqrt(3x-4))) ?
The domain of ((sqrt(x+4)))/((sqrt(3x-4))) is x> 4/3