What is the domain of f(x)=(3x+9)/(x^2+x-12) ?

The domain of f(x)=(3x+9)/(x^2+x-12) is x 3

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domain of f(x)=(3x+9)/(x^2+x-12)

domain

f (x) = \frac{3 x + 9}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = 5 \cdot 1 - x - 3

\frac{2 x + 1}{x - 5}

(\frac{- 3 x ^{2}}{2}) + \frac{225 x}{2}

(x^{\frac{2}{3}})^{3}

f (x) = \frac{1}{x ^{2} - 81}

What is the domain of f(x)=(3x+9)/(x^2+x-12) ?
The domain of f(x)=(3x+9)/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3