What is the domain of (sqrt(2x+1))/(x-5) ?

The domain of (sqrt(2x+1))/(x-5) is -1/2 5

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domain of (sqrt(2x+1))/(x-5)

domain

\frac{2 x + 1}{x - 5}

- \frac{1}{2} \leq x < 5 or x > 5

Interval Notation

[- \frac{1}{2}, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

- \frac{1}{2} \leq x < 5 or x > 5

(\frac{- 3 x ^{2}}{2}) + \frac{225 x}{2}

(x^{\frac{2}{3}})^{3}

f (x) = \frac{1}{x ^{2} - 81}

\frac{2 - x - 1 + 3}{x - 2}

f (x) = \frac{x + 7}{x - 9}

What is the domain of (sqrt(2x+1))/(x-5) ?
The domain of (sqrt(2x+1))/(x-5) is -1/2 <= x<5\lor x>5