What is the domain of f(x)=(sqrt(x+a^2-a))/x ?

The domain of f(x)=(sqrt(x+a^2-a))/x is x>=-a^2+a

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domain of f(x)=(sqrt(x+a^2-a))/x

domain

f (x) = \frac{x + a ^{2} - a}{x}

x \geq - a^{2} + a

Solution steps

Find non-negative values for radicals:

x \geq - a^{2} + a

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \geq - a^{2} + a

f (x) = \frac{3}{x - 2} + 10

3 x^{3} - 1

f (x) = - 6 t

f (x) = \frac{( x - 1 )}{25 - x ^{2}}

f (x) = \frac{7}{7 x + 1}

What is the domain of f(x)=(sqrt(x+a^2-a))/x ?
The domain of f(x)=(sqrt(x+a^2-a))/x is x>=-a^2+a