What is the domain of y=(sqrt(5-x))/(-4x+8) ?

The domain of y=(sqrt(5-x))/(-4x+8) is x<2\lor 2<x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(sqrt(5-x))/(-4x+8)

domain

y = \frac{5 - x}{- 4 x + 8}

x < 2 or 2 < x \leq 5

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq 5

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x < 2 or 2 < x \leq 5

\frac{4 x ^{2} + 1}{( - 2 x + 1 ) x}

f (x) = x^{2} y^{2} - 16 y^{2} + x - 8 = 0

f (x) = \frac{5}{( 4 x - 1 )}

\frac{x ^{2}}{lo g _{e} ( x )}

f (x) = \frac{2 x}{ln ( x )}

What is the domain of y=(sqrt(5-x))/(-4x+8) ?
The domain of y=(sqrt(5-x))/(-4x+8) is x<2\lor 2<x<= 5