What is the d/(do)(sqrt(2x+1)on[0.2]) ?

The d/(do)(sqrt(2x+1)on[0.2]) is 0.2nsqrt(2x+1)

What is the first d/(do)(sqrt(2x+1)on[0.2]) ?

The first d/(do)(sqrt(2x+1)on[0.2]) is 0.2nsqrt(2x+1)

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\frac{d}{d o} (2 x + 1 o n [0.2])

0.2 n 2 x + 1

Solution steps

\frac{d}{d o} (2 x + 1 o n (0.2))

Treat

n, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x + 1 n \cdot 0.2 \frac{d o}{d o}

Apply the common derivative:

\frac{d o}{d o} = 1

= 2 x + 1 n \cdot 0.2 \cdot 1

Simplify

= 0.2 n 2 x + 1

f (x) = \frac{( x ^{2} - 5 ) ^{3}}{125}

4 cos (x)

f (x) = 2 x^{3} + 3 x^{2} - 36 x - 5

f (x) = (x + 4)^{\frac{2}{3}}

f (x) = - 2 x + 5 ln (2 x)

What is the d/(do)(sqrt(2x+1)on[0.2]) ?
The d/(do)(sqrt(2x+1)on[0.2]) is 0.2nsqrt(2x+1)
What is the first d/(do)(sqrt(2x+1)on[0.2]) ?
The first d/(do)(sqrt(2x+1)on[0.2]) is 0.2nsqrt(2x+1)