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Popular >

extreme f(x)=2x^2-3x-1

Solution

extreme points

f (x) = 2 x^{2} - 3 x - 1

Solution

Minimum (\frac{3}{4}, - \frac{17}{8})

Solution steps

f^{'} (x) = 4 x - 3

Find intervals:

Decreasing

: - \infty < x < \frac{3}{4},

Increasing

: \frac{3}{4} < x < \infty

Plug

x = \frac{3}{4}

into

2 x^{2} - 3 x - 1 : - \frac{17}{8}

Minimum (\frac{3}{4}, - \frac{17}{8})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-3x-1 ?
The extreme f(x)=2x^2-3x-1 is Minimum(3/4 ,-17/8)