What is the extreme f(x)=-x^3+12x-11 ?

The extreme f(x)=-x^3+12x-11 is Minimum(-2,-27),Maximum(2,5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3+12x-11

extreme points

f (x) = - x^{3} + 12 x - 11

Minimum (- 2, - 27), Maximum (2, 5)

Solution steps

f^{'} (x) = - 3 x^{2} + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{3} + 12 x - 11 : - 27

Minimum (- 2, - 27)

Plug

x = 2

into

- x^{3} + 12 x - 11 : 5

Maximum (2, 5)

Minimum (- 2, - 27), Maximum (2, 5)

f (x, y) = (x - y) (36 - x y)

f (x) = x^{\frac{8}{3}}

f (x) = x^{2} - 9 y x^{2} - 7 x + 12

f (x) = 2 x^{3} - 9 x^{2} + 12 x + 6

f (x) = x + ln (1 - x)

What is the extreme f(x)=-x^3+12x-11 ?
The extreme f(x)=-x^3+12x-11 is Minimum(-2,-27),Maximum(2,5)