What is the extreme (2x-5)/(x^2-4) ?

The extreme (2x-5)/(x^2-4) is Minimum(1,1),Maximum(4, 1/4)

Popular >

extreme (2x-5)/(x^2-4)

extreme points

\frac{2 x - 5}{x ^{2} - 4}

Minimum (1, 1), Maximum (4, \frac{1}{4})

Solution steps

f^{'} (x) = \frac{- 2 x ^{2} + 10 x - 8}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 1,

Increasing

: 1 < x < 2,

Increasing

: 2 < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 1

into

\frac{2 x - 5}{x ^{2} - 4} : 1

Minimum (1, 1)

Plug

x = 4

into

\frac{2 x - 5}{x ^{2} - 4} : \frac{1}{4}

Maximum (4, \frac{1}{4})

Minimum (1, 1), Maximum (4, \frac{1}{4})

f (x, y) = x^{2} y + 3 x y^{2}

f (x) = x^{4} + y^{4} - 4 x y + 1

f (x) = \frac{3 x - 6}{x + 2}

f (x, y) = 1 - x^{2} + 2 y^{2}

f (x, y) = 60 x - 2 x^{2} - 3 y^{2} + 30 y

What is the extreme (2x-5)/(x^2-4) ?
The extreme (2x-5)/(x^2-4) is Minimum(1,1),Maximum(4, 1/4)