What is the extreme f(x)=3sin(x)+3cos(x) ?

The extreme f(x)=3sin(x)+3cos(x) is Maximum(pi/4+2pin,3sqrt(2)),Minimum((5pi)/4+2pin,-3sqrt(2))

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extreme f(x)=3sin(x)+3cos(x)

extreme points

f (x) = 3 sin (x) + 3 cos (x)

Maximum (\frac{π}{4} + 2 πn, 32), Minimum (\frac{5 π}{4} + 2 πn, - 32)

Solution steps

Find the critical points:

x = \frac{π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Domain of

3 sin (x) + 3 cos (x) : - \infty < x < \infty

Find intervals:

Increasing

: 2 πn \leq x < \frac{π}{4} + 2 πn,

Decreasing

: \frac{π}{4} + 2 πn < x < \frac{5 π}{4} + 2 πn,

Increasing

: \frac{5 π}{4} + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = \frac{π}{4} + 2 πn

into

3 sin (x) + 3 cos (x) \Rightarrow y = 32

Maximum (\frac{π}{4} + 2 πn, 32)

Plug the extreme point

x = \frac{5 π}{4} + 2 πn

into

3 sin (x) + 3 cos (x) \Rightarrow y = - 32

Minimum (\frac{5 π}{4} + 2 πn, - 32)

Maximum (\frac{π}{4} + 2 πn, 32), Minimum (\frac{5 π}{4} + 2 πn, - 32)

\frac{x ^{2}}{1 - x ^{2}}

f (x) = (x + 2)^{\frac{4}{3}}, - 6 \leq x \leq 6

f (x) = - x^{3} + 15 x^{2}

f (x) = \frac{x ^{2} - 14 x + 49}{x - 10}

f (x) = e^{x^{3} - 12 x}

What is the extreme f(x)=3sin(x)+3cos(x) ?
The extreme f(x)=3sin(x)+3cos(x) is Maximum(pi/4+2pin,3sqrt(2)),Minimum((5pi)/4+2pin,-3sqrt(2))