What is the extreme f(x)=2x^2-6x^4 ?

The extreme f(x)=2x^2-6x^4 is Maximum(-1/(sqrt(6)), 1/6),Minimum(0,0),Maximum(1/(sqrt(6)), 1/6)

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extreme f(x)=2x^2-6x^4

extreme points

f (x) = 2 x^{2} - 6 x^{4}

Maximum (- \frac{1}{6}, \frac{1}{6}), Minimum (0, 0), Maximum (\frac{1}{6}, \frac{1}{6})

Solution steps

f^{'} (x) = 4 x - 24 x^{3}

Find intervals:

Increasing

: - \infty < x < - \frac{1}{6},

Decreasing

: - \frac{1}{6} < x < 0,

Increasing

: 0 < x < \frac{1}{6},

Decreasing

: \frac{1}{6} < x < \infty

Plug

x = - \frac{1}{6}

into

2 x^{2} - 6 x^{4} : \frac{1}{6}

Maximum (- \frac{1}{6}, \frac{1}{6})

Plug

x = 0

into

2 x^{2} - 6 x^{4} : 0

Minimum (0, 0)

Plug

x = \frac{1}{6}

into

2 x^{2} - 6 x^{4} : \frac{1}{6}

Maximum (\frac{1}{6}, \frac{1}{6})

Maximum (- \frac{1}{6}, \frac{1}{6}), Minimum (0, 0), Maximum (\frac{1}{6}, \frac{1}{6})

f (x) = - x^{2} + 10, - 3 \leq x \leq 4

f (x, y) = - x^{2} - y^{2} + x + 2 y - 1

\frac{2}{x + 5}

f (x) = - 3 x^{3} - \frac{63}{2} x^{2} - 90 x + 1

f (x) = 3 + x + x^{2}

What is the extreme f(x)=2x^2-6x^4 ?
The extreme f(x)=2x^2-6x^4 is Maximum(-1/(sqrt(6)), 1/6),Minimum(0,0),Maximum(1/(sqrt(6)), 1/6)