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Popular >

extreme f(x)=sqrt(x^2+9)

Solution

extreme points

f (x) = x^{2} + 9

Solution

Minimum (0, 3)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} + 9}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 9 : 3

Minimum (0, 3)

Graph

Popular Examples

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\frac{4}{x + 6}

extreme f(x,y)=113x+15y-x^2-2y^2+3xy extreme points

f (x, y) = 113 x + 15 y - x^{2} - 2 y^{2} + 3 x y

extreme f(x)=-x^3+6x^2+15x+4 extreme points

f (x) = - x^{3} + 6 x^{2} + 15 x + 4

extreme (csc(x))/(1+csc(x))extreme points

\frac{csc ( x )}{1 + csc ( x )}

extreme f(x)=x^{8/3},-8<= x<= 1 extreme points

f (x) = x^{\frac{8}{3}}, - 8 \leq x \leq 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2+9) ?
The extreme f(x)=sqrt(x^2+9) is Minimum(0,3)