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Popular >

extreme f(x)=(x+2)^{4/3}

Solution

extreme points

f (x) = (x + 2)^{\frac{4}{3}}

Solution

Minimum (- 2, 0)

Solution steps

f^{'} (x) = \frac{4 ( x + 2 ) ^{\frac{1}{3}}}{3}

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

(x + 2)^{\frac{4}{3}} : 0

Minimum (- 2, 0)

Graph

Popular Examples

extreme f(x)=x^3-3x^2+1,-1/2 <= x<= 4 extreme points

f (x) = x^{3} - 3 x^{2} + 1, - \frac{1}{2} \leq x \leq 4

extreme f(x)=(x^2-10x+25)/(x-10)extreme points

f (x) = \frac{x ^{2} - 10 x + 25}{x - 10}

extreme f(x,y)=3x^2+xy-y^2 extreme points

f (x, y) = 3 x^{2} + x y - y^{2}

extreme f(x)=(x^5)/(20)-4x^3 extreme points

f (x) = \frac{x ^{5}}{20} - 4 x^{3}

extreme x^3+9x^2 extreme points

x^{3} + 9 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x+2)^{4/3} ?
The extreme f(x)=(x+2)^{4/3} is Minimum(-2,0)