What is the extreme f(x,y)=37-x^2-y^2 ?

The extreme f(x,y)=37-x^2-y^2 is Maximum(0,0)

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extreme f(x,y)=37-x^2-y^2

extreme points

f (x, y) = 37 - x^{2} - y^{2}

Maximum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(0, 0) :

Maximum

Maximum (0, 0)

f (x) = 0.09 x^{2} + 16 x + 350, 0 < x < 150

f (x) = - x^{2} + 5 x - 6, 2 \leq x \leq 3

f (x, y) = x^{3} - y^{2} - 6 x y - 4

f (x) = x^{2} - 6 x + 9

f (x) = \frac{x ^{3} + 2}{x}

What is the extreme f(x,y)=37-x^2-y^2 ?
The extreme f(x,y)=37-x^2-y^2 is Maximum(0,0)