en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(x^3+2)/x

Solution

extreme points

f (x) = \frac{x ^{3} + 2}{x}

Solution

Minimum (1, 3)

Solution steps

f^{'} (x) = \frac{2 x ^{3} - 2}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

\frac{x ^{3} + 2}{x} : 3

Minimum (1, 3)

Graph

Popular Examples

extreme f(x)=3(x-4)^{2/3}+6 extreme points

f (x) = 3 (x - 4)^{\frac{2}{3}} + 6

extreme f(x)=-4cos(3x)-4,(0,2pi)extreme points

f (x) = - 4 cos (3 x) - 4, (0, 2 π)

extreme f(t)=5-6u(t-2)+3u(t-5)extreme points

f (t) = 5 - 6 u (t - 2) + 3 u (t - 5)

extreme h(t,v)=-16t^2+vt+k extreme points

h (t, v) = - 16 t^{2} + v t + k

extreme f(x,y)=4x-8xy+2y+1 extreme points

f (x, y) = 4 x - 8 x y + 2 y + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^3+2)/x ?
The extreme f(x)=(x^3+2)/x is Minimum(1,3)