What is the extreme f(x)=0.09x^2+16x+350,0<x<150 ?

The extreme f(x)=0.09x^2+16x+350,0<x<150 is None

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extreme f(x)=0.09x^2+16x+350,0<x<150

extreme points

f (x) = 0.09 x^{2} + 16 x + 350, 0 < x < 150

None

Solution steps

Find the critical points:

None

0.09 x^{2} + 16 x + 350

has no critical points, therefore there are no extreme points

None

f (x) = - x^{2} + 5 x - 6, 2 \leq x \leq 3

f (x, y) = x^{3} - y^{2} - 6 x y - 4

f (x) = x^{2} - 6 x + 9

f (x) = \frac{x ^{3} + 2}{x}

f (x) = 3 (x - 4)^{\frac{2}{3}} + 6

What is the extreme f(x)=0.09x^2+16x+350,0<x<150 ?
The extreme f(x)=0.09x^2+16x+350,0<x<150 is None