What is the extreme h(t,v)=-16t^2+vt+k ?

The extreme h(t,v)=-16t^2+vt+k is Saddle(0,0)

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extreme h(t,v)=-16t^2+vt+k

extreme points

h (t, v) = - 16 t^{2} + v t + k

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 0

D (t, v) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x, y) = 4 x - 8 x y + 2 y + 1

+ 5^{x} - 4

f (x) = x^{3} - x^{2} - x + 6

x 6 - x

f (x) = x e^{\frac{2}{x}}

What is the extreme h(t,v)=-16t^2+vt+k ?
The extreme h(t,v)=-16t^2+vt+k is Saddle(0,0)