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Popular >

extreme f(x)=x^2-8x+10

Solution

extreme points

f (x) = x^{2} - 8 x + 10

Solution

Minimum (4, - 6)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 10 : - 6

Minimum (4, - 6)

Graph

Popular Examples

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f (x) = 6 + x - x^{2}

extreme f(x)=x^2+9x-5 extreme points

f (x) = x^{2} + 9 x - 5

extreme f(x)=(ln(x))/x ,1<= x<= 3 extreme points

f (x) = \frac{ln ( x )}{x}, 1 \leq x \leq 3

extreme f(x)= x/((x^2+9))extreme points

f (x) = \frac{x}{( x ^{2} + 9 )}

extreme f(x)=3x^4-4x^3+6 extreme points

f (x) = 3 x^{4} - 4 x^{3} + 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+10 ?
The extreme f(x)=x^2-8x+10 is Minimum(4,-6)