What is the extreme f(x)=11x_{1}+6x_{1}x_{2}+3x_{2} ?

The extreme f(x)=11x_{1}+6x_{1}x_{2}+3x_{2} is Saddle(-1/2 ,-11/6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=11x_{1}+6x_{1}x_{2}+3x_{2}

extreme points

f (x) = 11 x_{1} + 6 x_{1} x_{2} + 3 x_{2}

Saddle (- \frac{1}{2}, - \frac{11}{6})

Solution steps

Find the critical points:

(- \frac{1}{2}, - \frac{11}{6})

\frac{\partial ^{2} f}{\partial x _{1}^{2}} = 0

D (x_{1}, x_{2}) = - 36

Check the sign of at each critical point

Check critical point

(- \frac{1}{2}, - \frac{11}{6}) :

Saddle

Saddle (- \frac{1}{2}, - \frac{11}{6})

f (x) = 9 x^{4} - 26 x^{3} - 84 x^{2} + 72

f (x, y) = x^{3} + y^{2} - 3 x - 4 y

\frac{x ^{2} - 11}{x + 6}

f (x, y) = x^{3} - 12 x - 3 y + y^{3}

f (x) = - x^{3} + 3 x + 4

What is the extreme f(x)=11x_{1}+6x_{1}x_{2}+3x_{2} ?
The extreme f(x)=11x_{1}+6x_{1}x_{2}+3x_{2} is Saddle(-1/2 ,-11/6)