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Popular >

extreme y=x^3-3x^2+4x-4

Solution

extreme points

y = x^{3} - 3 x^{2} + 4 x - 4

Solution

None

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 4

Find intervals:

None

None

Graph

Popular Examples

extreme f(xy)=xy extreme points

f (x y) = x y

extreme f(x)=2x^3-3x^2-12x+18 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 18

extreme f(x)=x^3-3x^2-9x+1,0<= x<= 5 extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 1, 0 \leq x \leq 5

extreme f(x,y)= 1/4 x^4-1/2 x^2+y^2 extreme points

f (x, y) = \frac{1}{4} x^{4} - \frac{1}{2} x^{2} + y^{2}

extreme f(x)=x+4/(x^2)extreme points

f (x) = x + \frac{4}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-3x^2+4x-4 ?
The extreme y=x^3-3x^2+4x-4 is None