What is the extreme f(x)=(x-2)(x+1)(x+4) ?

The extreme f(x)=(x-2)(x+1)(x+4) is Maximum(-1-sqrt(3),6sqrt(3)),Minimum(-1+sqrt(3),-6sqrt(3))

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extreme f(x)=(x-2)(x+1)(x+4)

extreme points

f (x) = (x - 2) (x + 1) (x + 4)

Maximum (- 1 - 3, 63), Minimum (- 1 + 3, - 63)

Solution steps

f^{'} (x) = 3 (x^{2} + 2 x - 2)

Find intervals:

Increasing

: - \infty < x < - 3 - 1,

Decreasing

: - 3 - 1 < x < 3 - 1,

Increasing

: 3 - 1 < x < \infty

Plug

x = - 1 - 3

into

(x - 2) (x + 1) (x + 4) : 63

Maximum (- 1 - 3, 63)

Plug

x = - 1 + 3

into

(x - 2) (x + 1) (x + 4) : - 63

Minimum (- 1 + 3, - 63)

Maximum (- 1 - 3, 63), Minimum (- 1 + 3, - 63)

f (x) = x^{3} - 3 x - 3

x^{2} + y^{2} - x y

f (x) = 14 x^{2} - 2 x^{3} + 4 x y

f (x) = ln (x^{2} + 7 x + 15)

f (x) = - \frac{2}{x ^{2}}

What is the extreme f(x)=(x-2)(x+1)(x+4) ?
The extreme f(x)=(x-2)(x+1)(x+4) is Maximum(-1-sqrt(3),6sqrt(3)),Minimum(-1+sqrt(3),-6sqrt(3))