What is the extreme f(x)=x-(-4)x^{-1} ?

The extreme f(x)=x-(-4)x^{-1} is Maximum(-2,-4),Minimum(2,4)

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extreme f(x)=x-(-4)x^{-1}

extreme points

f (x) = x - (- 4) x^{- 1}

Maximum (- 2, - 4), Minimum (2, 4)

Solution steps

f^{'} (x) = 1 - \frac{4}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x - (- 4) x^{- 1} : - 4

Maximum (- 2, - 4)

Plug

x = 2

into

x - (- 4) x^{- 1} : 4

Minimum (2, 4)

Maximum (- 2, - 4), Minimum (2, 4)

f (x) = x + \frac{5}{x}

y = x 36 - x^{2}

x^{2} - 8 ln (x)

f (x, y) = x y^{2} - 6 x^{2} - 3 x + 2 x y + 9

f (p, q) = pq - \frac{1}{p} - \frac{1}{q}

What is the extreme f(x)=x-(-4)x^{-1} ?
The extreme f(x)=x-(-4)x^{-1} is Maximum(-2,-4),Minimum(2,4)