What is the extreme f(x)=9x^3-54x^2+81x+13,(-6,2) ?

The extreme f(x)=9x^3-54x^2+81x+13,(-6,2) is Maximum(1,49)

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extreme f(x)=9x^3-54x^2+81x+13,(-6,2)

extreme points

f (x) = 9 x^{3} - 54 x^{2} + 81 x + 13, (- 6, 2)

Maximum (1, 49)

Solution steps

Find the critical points:

x = 1

Domain of

9 x^{3} - 54 x^{2} + 81 x + 13, (- 6, 2) : - 6 < x < 2

Find intervals:

Increasing

: - 6 < x < 1,

Decreasing

: 1 < x < 2

Plug the extreme point

x = 1

into

9 x^{3} - 54 x^{2} + 81 x + 13 \Rightarrow y = 49

Maximum (1, 49)

f (x) = x^{3} - 12 x^{2} + 45 x + 7

f (x) = x^{7} (x + 4)^{4}, - 10 \leq x \leq 13

y = x^{4} - 8 x^{2} + 5

f (x) = (x - 7) e^{x}

y (x, t) = 3 x + 2 a t (3.4)

What is the extreme f(x)=9x^3-54x^2+81x+13,(-6,2) ?
The extreme f(x)=9x^3-54x^2+81x+13,(-6,2) is Maximum(1,49)