What is the extreme f(x)=(x^3)/3-6x^2 ?

The extreme f(x)=(x^3)/3-6x^2 is Maximum(0,0),Minimum(12,-288)

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extreme f(x)=(x^3)/3-6x^2

extreme points

f (x) = \frac{x ^{3}}{3} - 6 x^{2}

Maximum (0, 0), Minimum (12, - 288)

Solution steps

f^{'} (x) = x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 12,

Increasing

: 12 < x < \infty

Plug

x = 0

into

\frac{x ^{3}}{3} - 6 x^{2} : 0

Maximum (0, 0)

Plug

x = 12

into

\frac{x ^{3}}{3} - 6 x^{2} : - 288

Minimum (12, - 288)

Maximum (0, 0), Minimum (12, - 288)

f (x) = - x^{3} + 12 x - 14

f (x) = 200 - 8 y = 0

f (x) = (x - 5) ln (x - 5)

f (x) = x^{2} + 5 x + 6

f (x) = 2 sec (x) - tan (x)

What is the extreme f(x)=(x^3)/3-6x^2 ?
The extreme f(x)=(x^3)/3-6x^2 is Maximum(0,0),Minimum(12,-288)