What is the extreme f(x)=6x^3-9x^2-108x+9 ?

The extreme f(x)=6x^3-9x^2-108x+9 is Maximum(-2,141),Minimum(3,-234)

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extreme f(x)=6x^3-9x^2-108x+9

extreme points

f (x) = 6 x^{3} - 9 x^{2} - 108 x + 9

Maximum (- 2, 141), Minimum (3, - 234)

Solution steps

f^{'} (x) = 18 x^{2} - 18 x - 108

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

6 x^{3} - 9 x^{2} - 108 x + 9 : 141

Maximum (- 2, 141)

Plug

x = 3

into

6 x^{3} - 9 x^{2} - 108 x + 9 : - 234

Minimum (3, - 234)

Maximum (- 2, 141), Minimum (3, - 234)

f (x) = x e^{6 x}

f (x, y) = e^{- x^{2} - y^{2}} (x^{2} + 2 y^{2})

f (x) = x^{3} - 27 x + 58

f (x) = \frac{x}{x ^{2} - 36}

f (x, y) = 32 y^{2} + x^{2} - x^{2} y

What is the extreme f(x)=6x^3-9x^2-108x+9 ?
The extreme f(x)=6x^3-9x^2-108x+9 is Maximum(-2,141),Minimum(3,-234)